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Mathematics 8 Online
OpenStudy (anonymous):

solve x/7-7/x=0

OpenStudy (acxbox22):

x=7

OpenStudy (anonymous):

1) multiply out the denominators (ie. multiply both sides of the equation by x then 7. Do this and tell me what you get.

OpenStudy (anonymous):

you should get \[x ^{2}-49=0\]

OpenStudy (anonymous):

Did you get this?

OpenStudy (anonymous):

yes what next

OpenStudy (anonymous):

Are you familiar with the "difference of two squares" rule?

OpenStudy (anonymous):

yes

OpenStudy (acxbox22):

just add 49 to both sides and take its squareroot

OpenStudy (anonymous):

|dw:1397615403507:dw|

OpenStudy (acxbox22):

much easier you are doing the same thing but in a longer way

OpenStudy (anonymous):

|dw:1397615457872:dw|

OpenStudy (anonymous):

So can you see that the equation is \[x ^{2}-7^{2}\] this factorises out into \[(x-7)(x+7)=0 \] ...voila... or you can use acxbox22's method!

OpenStudy (anonymous):

Do you understand?

OpenStudy (anonymous):

yes a little whaat is that method like how do i do it

OpenStudy (anonymous):

So, \[x ^{2}-49=0 ... x ^{2}=47 ....x=+ or - \sqrt{47} ....=+ or - 7\] You simply take the square root. But the crucial step is to say "plus or minus" the square root. Because it could be either - there are two solutions

OpenStudy (anonymous):

can you walk me through it slowly please

OpenStudy (anonymous):

Do you want to know how to solve an equation?

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