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Mathematics 9 Online
OpenStudy (vera_ewing):

If the perimeter of triangle A is 16 in., the perimeter of triangle B is 8 in., and the area of triangle A is 160 in2 what is the area of triangle B if triangle A is similar to triangle B? @RadEn

OpenStudy (anonymous):

similar means the triangles sides are proportional! do you need further help?

OpenStudy (vera_ewing):

@whpalmer4 please help?

OpenStudy (vera_ewing):

@thomaster @Luigi0210 @bahrom7893 can you guys please help? i'm so confused...

OpenStudy (vera_ewing):

@AravindG please

OpenStudy (anonymous):

if it's as simple as I'm hopefully not mistakenly making it to be, since the triangles are similar and so proportional since the perimiteter of triagngle a is double the perimeter of triangle b then that means the area should be double So like a porportion 8/16 must equal x/160 half of 160 is 80 so the area is 80 ****** I'll be honest I am not sure if this is correct***

OpenStudy (vera_ewing):

@AravindG is this right?

OpenStudy (aravindg):

This link is very useful http://www.mathwarehouse.com/geometry/similar/triangles/area-and-perimeter-of-similar-triangles.php Ratio of areas=(similarity ratio)^2

OpenStudy (aravindg):

They follow a squared relations instead of a linear one.

OpenStudy (vera_ewing):

Ok so 80 is the correct answer?

OpenStudy (vera_ewing):

I just don't want to get it wrong :)

OpenStudy (aravindg):

No. You got to square the ratio of perimeters.

OpenStudy (vera_ewing):

Ohh, so 40^2?

OpenStudy (anonymous):

the ratio of the perimiteers is the smaller perimeter triangle divided by the higher perimeter triangles 8/16 which equals 1/2 square it and it euwals 1/4

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