Convert into perfect square + some constant

Question

anonymous · Answer

x^2+x

anonymous · Answer

I didn't get what the question meant

mathmale · Answer

Hello!  We are given:  x^2+x and want to express this as a perfect square of a binomial, plus a constant.   Here's what the form of your answer should look like:  (x+a)^2 + b.

anonymous · Answer

what will it be

mathmale · Answer

I'll guide you through the problem solution.  Need your participation.

Given   x^2+x, rewrite this as x^2 + 1x.  Note that the coefficient of x is ' 1 '.  
Take half of 1.  Square the result.  What do you get?

anonymous · Answer

0.25

mathmale · Answer

Seriously:  What is "half of one?"

Good.  It's 1/2.  The square of that is 1/4, or, as you have written, 0.25.

mathmale · Answer

Take your x^2 + 1x and FIRST add 1/4 to it, and then subtract 1/4 from it.  Write everything out.

anonymous · Answer

x^x +x + 1/4 -1/4
(x+0.5)^2 -1/4     <------- right

mathmale · Answer

Cool!  You've got it!  congrats.

anonymous · Answer

Like quadratics completing the square I feel so dumb might be because I have been doing maths from last 7 hours maybe. thank u

mathmale · Answer

My great pleasure.  Hope to work with you again soon!