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Mathematics 20 Online
OpenStudy (anonymous):

HELP ME PLSSSSSSS ill show picture

OpenStudy (anonymous):

OpenStudy (anonymous):

guys i hav to go take a big test but ill b bak to see what yall said

OpenStudy (anonymous):

Do u know similarity

OpenStudy (johnweldon1993):

Hmm...well |dw:1397653744508:dw| If we know that \(\large x = \frac{216}{y}\) We can substitute that into our ratio equation \[\huge \frac{\frac{216}{y}}{y} = \frac{48}{54}\] Lets simplify that left side there \[\huge \frac{216}{y^2} = \frac{48}{54}\] Now cross multiply and isolate y^2 \[\large y^2 = \frac{(216 \times 54)}{48}\] ad \[\large y = \sqrt{\frac{(216 \times 54)}{48}}\] Once you solve for that 'y' plug it into the original ratio again to solve for 'x' After that you can check to see if you received the correct results by evaluating the ratios

OpenStudy (anonymous):

@johnweldon1993

OpenStudy (johnweldon1993):

Alright what do you need help with :)

OpenStudy (anonymous):

ok this is what my study plan shows me to do |dw:1397670508748:dw|

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