Question

math helppp!!!!

Answer 1

The average height of a sunflower is 64 inches with a standard deviation of 3.5 inches. Label the horizontal axis of the normal curve of distribution below. In the boxes, include the approximate percentages of data that fall in that region. (6 points)
_____ _____ _____ _____ _____ _____ _____
b. If there are 3,000 sunflowers in the field, approximately how many will be taller than 71 inches?
c. If there are 3,000 sunflowers in the field, approximately how many will be between 60.5 inches and 67.5 inches?

Answer 2

can you do any of this ?

Answer 3

I can do b and c I just need help with a I don't understand how to do it

Answer 4

ok I'm here

Answer 5

the bottom row of blanks (in blue) you get by adding the standard deviation to the mean
can you do that ?

Answer 6

the blank directly beneath the mean *is the mean* i.e. is 64

Answer 7

it seems like you having a moderater helping you right now. You are very lucky!

Answer 8

so it would be 67.5?

Answer 9

the blank directly below the mean is 64.
the blank below the line labeled +1 standard deviation is 67.5

Answer 10

keep following that pattern. the blank below +2 standard deviations is what ?

Answer 11

69.5?

Answer 12

how did you get that ?

Answer 13

I did 64+3.5+2

Answer 14

you don't add 2, you add 2 standard deviations
a standard deviation is 3.5

Answer 15

each time you move over 1 standard deviation, you add 3.5

Answer 16

so it would be 71?

Answer 17

think like this:
start at the middle (the mean). It is 64
now each time you move to the right one "line" add 3.5. You count up by 3.5 from answer to answer.

Answer 18

okay so it would be 64 then 67.5 then 71 then 74.5

Answer 19

how would I figure out the percentage

Answer 20

yes, and the something (but subtracting) for the blanks on the left side of the mean

for the areas, see
https://en.wikipedia.org/wiki/Standard_deviation

Answer 21

*samething

Answer 22

how do I find the percentages

Answer 23

you could also look in a table and find the probability of being between 0 and 1 standard deviation, and then between 1 and 2, and 2 and 3

or look at the graph at at the wikipedia link.

Answer 24

would the percentage between 64 and 67.5 be 0.95% ?

Answer 25

First, the total area under the curve adds up 100%
0.95% is about 1% or 1/100 of the total area. Looking at the picture, you can see that the area between the mean and + 1 standard deviation is a big "chunk" of the total area (not 1% !)

How did you get 0.95% ?

Answer 26

I did \[\frac{ 64 }{ 67.5? }\]

Answer 27

Do you have a table that you use for these problems ?

Answer 28

no I dnt think so

Answer 29

Have you heard of a "normal distribution table" ?

Answer 30

no I havent

Answer 31

Can you go to this link
https://en.wikipedia.org/wiki/Standard_deviation

Answer 32

The numbers you need are shown in the curve to the right.
You need those numbers to answer parts b and c of this question.

Answer 33

https://www.stat.tamu.edu/~lzhou/stat302/standardnormaltable.pdf is this the table

Answer 34

yes

Answer 35

how I have the table how do I find the % using it

Answer 36

The wiki link gives the numbers directly.
Or you can use your table. Which do you want to do ?

Answer 37

are these the %

Answer 38

look at the 2nd half, for z=0.0 and look at the number in the first column (labeled .00)
do you see the entry , 0.5 ?

Answer 39

actually it shows 0.50000
that means 0.5 of the area (i.e. ½ of the total area) is to the left of the mean (the mean is at 0 standard deviations)