Question

Can someone explain how to graph f(x) = log base 2 (x - 3) + 1

Answer 1

The base 2 is like the exponent but its lower than the log instead of higher

Answer 2

By far the easiest way would be to graph \[y=\log_{2} x~ first,\] for positive x first.

Answer 3

Once you have that, we'll merely shift the graph around a bit.

Answer 4

Can you explain how to do that please?

Answer 5

I really do not understand logarithms and how to graph them so any help is welcome

Answer 6

We're discussing the log to the base 2 of x\[y=\log_{2}x \]The easiest way I know of doing this consists in picking values for x that are powers of 2: For example, 2, 2^2, 2^3, 2^4.

Please recall that the log and the exponential functions are inverses of each other, so that\[2^{\log_{2}x }=x~and \log_{2} 2^y=y\]