Question

Solve the following equation analytically.
6e^2x = 24e^−6x

Answer 1

Suggestion: Take the natural logarithm of each side of the equation.

Answer 2

how would i begin that?

Answer 3

\[\ln 6e ^{2x} = \ln 6 + 2x
and
\ln 24e ^{-6x} = \ln 24 - 6x\]
You now have the more familiar ln 6 + 2x = ln 24 - 6x. ln 6 might look horrible but it's just a constant term.