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Mathematics
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Solve the following equation analytically. 6e^2x = 24e^−6x
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Suggestion: Take the natural logarithm of each side of the equation.
how would i begin that?
\[\ln 6e ^{2x} = \ln 6 + 2x and \ln 24e ^{-6x} = \ln 24 - 6x\] You now have the more familiar ln 6 + 2x = ln 24 - 6x. ln 6 might look horrible but it's just a constant term.
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