OpenStudy (anonymous):

Given that IHJ is equiangular, find x and y.

OpenStudy (anonymous):

OpenStudy (ganeshie8):

hint : equiangular => each angle = 60

OpenStudy (anonymous):

This is a pretty cool problem. As ganeshie8 said, if a triangle is equiangular, all angles must equal 60. Look at angle <KJL, which measures 57. Since HL is a straight line, the total angle must be 180. We have 60 + 57 + x = 180. Solve for x to get one angle of the middle triangle.

OpenStudy (anonymous):

@bloopman thank you ! :)

OpenStudy (anonymous):

That's not the x/y YOU want, though. If you can solve for x in that equation we can continue the problem

OpenStudy (anonymous):

x=63

OpenStudy (anonymous):

We know that JK is congruent to IK. Therefore, <IJK must be congruent to <JIK. To find the last angle of the triangle we solve: 2*63 + a = 180