Divide the following polynomials using synthetic division (x^3 - 2x^2 - 1) ( x - 1)
First of all, have you done synth. div. before?
If your divisor in long division is x-1, then the corresponding divisor for synth. div. is +1 (yes, that's the opposite sign).
yes. my answer is x^2 - 2x + 1 1/x-1. but I received partial credit
The given polynomial (which we call the dividend) is of the third order (the highest x power is 3). What are the coefficients of this polynomial? Think very carefully.
Hint: x^3, x^2 and a constant show up in the given polynomial. What happened to the x?
it was subtracted
Actually, x does not show up at all where the 3rd term normally would be. So, in setting up your synth. div., you should use the coeff. 1 -2 0 and -1.
Try doing this synth. div.: 1 | 1 -2 0 -1 ----------------- and see what you get.
1 | 1 -2 0 -1 ----------------- 1
1 -3 -3 2
1 | 1 -2 0 -1 1 ----------------- 1 -1 Compare yours and mine. Can you finish the synth. div. now? If not, what do you need to know to do so?
1 -1 -1 -2
?
that's great. 1, -1 and -1 are the coefficients of the quotient, which is what you wanted to find. That -2 is your remainder. Take these 3 coefficients, please, and write out the corresponding polynomial.
x^2 - 1x - 1 2/x-1?
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