Find the indicated limit, if it exists
ill help right now
We have a piecewise function here. In order for the limit to exist, it has to approach the same value from the lefthand side and the righthand side. The function at the top is the left hand side, because it goes from -inf to 9. The function at the bottom is the right hand side, goes from 9 to inf. When you plug 9 in for x, do both parts of piecewise equal the same?
yes
would the limit be 9 then?
No, try again. :3 If you plug in 9 for x into each part of the piecewise function, what would the value be? (9) + 9 = ? 27 - (9) = ? If the answer are the same, then the limit as x approaches 9 will be that answer.
so the limit would be the answer? So 18
Yes, the limit as x approaches 9 will be 18. Since the piecewise function approaches 18 from both the left and right, as proven in the plug-n-chug, then the limit exists. :)
What about the limit of this question? @iPwnBunnies
Hmm, ok. Let's do the simple plug-n-chug, let's see if the limit exists like that. What happens when you plug 7 in for x?
7-7 = 0
Ok, sorry. So yeah, when you plug in 7, you get 7-7 in the denominator. This is sorta like a rule of limits: \[\lim_{x \rightarrow 7}\frac{1}{(7-7)^{2}} = \lim_{x \rightarrow 7} \frac{1}{0} = infinity \]
There is no other way to simplify the function. So, if you take the limit of something, and you get 0 in the denominator after trying EVERYTHING, then the limit will approach infinity.
http://www.wolframalpha.com/input/?i=limit+as+x+approaches+7+of+1%2F%28x-7%29%5E2
Limit = infinity Vertical Asymptope = 7
asymptote*
Yeah, there will also be a vertical asymptote at x = 7
what if we approached the limit from the left side? will the limit still be infinity?
or would it be - infinity?
Take a look at the graph I gave you the link to. It's kinda difficult to do it mathematically. Do you see how the graph approaches infinity from both the left and the right of the asymptote?
aha. Thanks!
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