Given the parent functions f(x) = 5x-1 and g(x) = 3^x -9 what is gx-fx
just subtract them,
like this : \(\large g(x) - f(x) = 3^x-9 - (5x-1)\) simplify
i got it :D
Can you help with another
sure :)
given the parent functions f(x) = log3 (5x-5) and gx = log 3 (x-1) what is f(x) - g(x)
did you try to subtract them ? then use the log property that \(\large \log_ab -\log_a c = \log_a (\dfrac{b}{c})\)
no..so I should do the numbers first before log?
no, i meant this : \(\large f(x)-g(x) = \log_3 (5x-5)- \log_3 (x-1 ) \\ \large = \dfrac{\log_3 (5x-5)}{\log_3(x-1)}\) got this ?
I never really understood log at alll!
sorry, that should be \(\large f(x)-g(x) = \log_3 (5x-5)- \log_3 (x-1 ) \\ \large = \log_3 \dfrac{ (5x-5)}{(x-1)}\) and logs are not difficult. here, i used the property that , differences of log equals log of ratio
Oh ok I see what you did there! What should be the next step?
factor out 5 from 5x-5
5(x-1) and not that x-1 gets cancelled from numerator and denominator :)
yeah so x-1 will stay and you have 5(x-1)
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