A large emerald with a mass of 378.24 grams was recently discovered in a mine. If the density of the emerald is 3.91grams over centimeters squared, what is the volume? Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point.

Question

anonymous · Answer

@phi can you help?

anonymous · Answer

@jim_thompson5910 ?

jim_thompson5910 · Answer

The density formula is 

D = M/V

where

D = density
M = mass
V = volume

jim_thompson5910 · Answer

what two things do we know?

anonymous · Answer

well i know the mass is 378.24

jim_thompson5910 · Answer

what else does it give you

anonymous · Answer

3.91$$\frac{ grams }{ cm ^{2} }$$

jim_thompson5910 · Answer

so 

D = 3.91
M = 378.24
V = unknown (leave it as V for now)

jim_thompson5910 · Answer

plug them into the given formula to get


D = M/V


3.91 = 378.24/V


now solve for V

anonymous · Answer

okay, so i would multiply by 378.24?

jim_thompson5910 · Answer

first you multiply both sides by V to get


3.91 = 378.24/V


3.91V = 378.24

jim_thompson5910 · Answer

then you divide both sides by 3.91 to completely isolate V

anonymous · Answer

oh okay.

anonymous · Answer

96.73

jim_thompson5910 · Answer

what are you getting after the 3?

jim_thompson5910 · Answer

give me 6 decimal places of what you're getting

anonymous · Answer

oh my bad. 96.74

jim_thompson5910 · Answer

good, you rounded properly this time


You'll get V = 96.7365728900256 which rounds to V = 96.74

anonymous · Answer

i got it....thank you!

jim_thompson5910 · Answer

yw