Question

can someone help out with algebra 1 work?????

Answer 1

sashajj: would you please post your questions first and ask the "can someone help" question later on?

Answer 2

choose the slope-intercept equation of the line that passes through the point shown and is perpendicular to the line shown.

Answer 3

y = one thirdx - 8
y = -3x + 12
y = 3x - 24
y = -one thirdx - 4

Answer 4

my bad

Answer 5

ok sorry

Answer 6

anyone????

Answer 7

did you graph all of the answer options??

Answer 8

yes

Answer 9

okay which one did you think it was?

Answer 10

second one

Answer 11

i think you are correct i didn't read the question right sorry

Answer 12

are u sure

Answer 13

one second @whpalmer4 is this correct??

Answer 14

im pretty sure that its the second one

Answer 15

if i get this wrong im probably screwed because have 5 questions and i need all right
and im not sure with the other once

Answer 16

sure

Answer 17

1 sec

Answer 18

slope of the line in the figure is 3
slope of the perpendicular line will be -1/3

line with slope -1/3 through point (6,-6) will be

\[y-(-6) = -\frac{1}{3}(x-6)\]
\[y + 6 = -\frac{1}{3}x+2\]\[y=-\frac{1}{3}x-4\]

Answer 19

Consider the line that passes through the points (0, 4) and (-1, 3). Below are two different equations. Identify the true statement concerning both equations.
Equation #1 = y - 4 = 1(x - 0)
Equation #2 = y - 3 = 1(x - 1)

Answer 20

1.Only equation #1 represents the line that passes through the two given points.
2.Only equation #2 represents the line that passes through the two given points.
3.Both equation #1 and equation #2 represent the line that passes through the two given points.
4.Neither equation #1 nor equation #2 represents the line that passes through the two given points.

Answer 21

For that first question, the 4th answer choice is the correct one, not the 2nd.

To consider the second question, the form they are using is

\[y - y_1 = m(x-x_1)\]Giving the equation of a line with slope \(m\) passing through point \((x_1,y_1)\)

Answer 22

You should calculate the slope of the line passing through (0,4) and (-1,3) as a first step. Is it what the two equations assume it is?

Answer 23

yes

Answer 24

Good. If it isn't, then we'd obviously choose answer #4.

Answer 25

So are the two equations provided the equations you would get if you plugged m = 1 and the two points given into my point-slope formula?

Answer 26

I encourage you to examine them very carefully before answering :-)

Answer 27

yes they are the equations u would get if plugged m = 1

Answer 28

I'm afraid not...

\((0,4)=(x_1,y_1)\)

\[y-y_1=m(x-x_1)\]\[y-4=1(x-0)\]

\((-1,3)=(x_1,y_1)\)
\[y-y_1 = m(x-x_1)\]\[y-3 = 1(x-(-1))\]

Still thinking that is the same equation they gave you?

Answer 29

im so confused

Answer 30

@sashajj: Are you still focused on the first of these 5 problems? In other words, given the graph, are you supposed to find the equation of a line perpendicular to the given (graphed) line and passing through the point (6,-6)?

Answer 31

ya i have been doing this for the past 3 hours and im not even sure if i did it right
im confused with the last question i wrote here and i need 20 shots

Answer 32

Let's give it another try.
First I need to be sure that you know two key facts.
1) if two lines are perpendicular, their slopes are negative reciprocals of one another.
Example: if the slope of that line in the illustration is 3, then the slope of a line
perpendicular to it is -1/3, which is the "negative reciprocal" of 3. OK so far?

Answer 33

2. Given the slope of a straight line and one point on the line, the equation of the line is
\[y-y _{0}=m(x-x _{0)}\]

Answer 34

@sashajj: working on a different problem right now? If so, come back here when you can; we're not that far from finishing this problem!