Question

Figure drawn below

Answer 1

In the given figure(circle) PT=5 , PD=7 and PA=2 then find the value of PB-PC

Answer 2

@mathslover

Answer 3

Just give me one minute.. :)

Answer 4

Ok no problem

Answer 5

I am still trying..

Answer 6

i am too

Answer 7

We might have to do some construction i get a intuition

Answer 8

I think I got it..

Answer 9

Tangent Secant Theorem will be used here.

PC * PD = PT^2

Answer 10

and PA * PB = PT^2

Answer 11

PC*PD=PA*PB=25

Answer 12

Actually it would be PT^2=PC*(PC+PD)

Answer 13

Or , just do like this :

\(\bullet \quad PC = \cfrac{PT^2}{PD} \\
PC = \cfrac{25}{7} \\

\bullet \quad PB = \cfrac{PT^2}{PA} \\
PB = \cfrac{25}{2} \\ \)

Answer 14

Actually it would be PT^2=PC*(PC+PD)

Answer 15

By tangent secant theorem

Answer 16

http://www.proofwiki.org/wiki/Tangent_Secant_Theorem

Answer 17

Yes, right, so it will be PT^2 = PC(PC + CD) = PC (PD)

that's what I wrote... :)

Answer 18

Sry

Answer 19

No problem.. Can you solve it now..

Answer 20

YES thank you!!

Answer 21

You're welcome :)