Question

solve to get x : log⁡(x^2+1)=1

Answer 1

the only way for \(\log(x^2+1)=1\) is if \(x^2+1=10\)

Answer 2

assuming of course that than means log base ten

\[\log_{10}(A)=B\iff A=10^B\]

Answer 3

A little confused...
would it be x^2+1=log10(1) ? ....

Answer 4

noooo
\[\Large \log(x^2+1)=1\\\Large 10^{\log(x^2+1)}=10^1\\\Large x^2 +1 =10\]

Answer 5

Ohhh and then x^2=10-1 -> x^2=9 and the x=sqrt(9) which then would be 3, @PeterPan ?

Answer 6

3 or something else ;)
And this is all assuming that the log is log base 10 ok? ^.^

Answer 7

Aaaalright.... -.- I'll figure it out hopefully. Thanks anyways, @PeterPan

Answer 8

besides, the more proper way of solving
x^2 - 9 = 0
is by factoring
^.^

That gives you the two solutions you need, yes?

Answer 9

I need two solutions? The question just says, solve the functions:/

Answer 10

Yes, but there are two possible answers to x^2 - 9 = 0

Did you try -3?

I didn't think so :P
Silly Sulle :D

Answer 11

Ahh it could be. But hell. I just want to get it as close to the right answer as possible. this'll do :P Thanks though, @PeterPan ! :D Love the username

Answer 12

It'd be better if we could be a little more sure, though...
Oh well, guess it can't be helped~ see you around :3