Question

MEDAL AND FANNED

http://prntscr.com/3aqtl6

Answer 1

@Zale101

Answer 2

if the circle passes through the point (1,9) and the center is (4,4)
so find both of there distances, from the center of the circle to the given poit will define the radius
Distance =\[\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]
r=\[\sqrt{(4-1)^2+(4-9)^2}\]
r=\[\sqrt{(3)^2+(-5)^2}\]
r=\[\sqrt{9+25}\]
r=\[\sqrt{34}\]
approximately 5.8 is the radius

Circle equation is
\[(x-x_1)^2+(y-y_1)^2 =r^2 \]
or
\[(x-h)^2+(y-k)^2 =r^2 \]
where the center of the circle is (h,k)

Center is (4,4)

\[(x-4)^2+(y-4)^2 =5.8^2 \]

Answer 3

first formula was the distance formula
d = sqr( (x2 - x1)^2 + (y2 -y1)^2 )

Answer 4

okay thank you

Answer 5

anytime