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Let \(S\) be a subset of an inner product space \(X\). Show that \(S^{\perp}\) is a closed linear subspace of \(X\).
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I just need the closed part @eliassaab
Let z be in the closure of \( S^{\perp} \), the ther is a sequence \( z_n\in S^{\perp}\) converging to z, let \( x\in S\) then \[ <x, z> = < x, \lim_{n\to \infty} z_n>=\lim_{n\to \infty} < x, \ z_n>=0 \]
man, you are good at this:)
everytime you answer something you make it seem trival
Meh, Math Majors.
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@zzr0ck3r Thanks
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