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d/dy tan inverse (y/x)
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Apply chain rule.
please solve that
Don't expect direct worked out answers here. I can guide you to the answer though.
plzzzzzzzzzzzzzzzzzz
Treat y/x=k And first differentiate tan inverse part. Then chain rule.
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Try what I said.
ok thn got that
So you got the final answer?
yes
If you can write it here I can check it. Else if you are confident then its okay :)
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1/x(xsquare +y square)
Not exactly derivative of tan-1 y/x \[\dfrac{1}{1+(y/x)^2} \times \dfrac{1}{x}\] That leaves us with x on numerator instead of x on denominator.
sorry integration of that
integration of cos square
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