FOR THIS I GOT D. Am i right? Solve the system of equations by substitution. What is the solution for x?

2x + y = 1
4x + 2y = -1

x = 0

x = 2

There is no x value as there is no solution.

x can be any value as there is an infinite number of solutions.

Question

FOR THIS I GOT D. Am i right?  Solve the system of equations by substitution. What is the solution for x?

2x + y = 1
4x + 2y = -1

x = 0

x = 2

There is no x value as there is no solution.

x can be any value as there is an infinite number of solutions.

ganeshie8 · Answer

|dw:1397739574286:dw|

ganeshie8 · Answer

2x + y = 1
4x + 2y = -1

These are two parallel lines, they never meet.

anonymous · Answer

So i am right?

ganeshie8 · Answer

you can figure that they're parallel by dividing the second equation by 2

ganeshie8 · Answer

dividing the second equation by 2, and subtracting gives :

2x + y = 1
2x + y = -1/2
-----------------
   0      =  3/2

which is FALSE.

ganeshie8 · Answer

so, there will not be any solutions.

ganeshie8 · Answer

and nope, D is not correct as it says there are infinitely many solutions.

anonymous · Answer

So C

ganeshie8 · Answer

yup ! C is correct

anonymous · Answer

Can you help me with2 more that i haven't figured out?

ganeshie8 · Answer

shoot...

anonymous · Answer

Solve the following system of equations:

x - 2y = 14
x + 3y = 9

(1, 12)

(-1, -12)

(12, -1)

(12, 1)

anonymous · Answer

Solve the system of equations.

x + 3y = -1
2x + 2y = 6

(-4, 1)

(2, -1)

(4, -1)

(5, -2)