6. Find B ∪ D. B: {–3, –1, 3, 4, 9, 11} D: {numbers divisible by 3 from 1 to 15} (1 point) {3, 9} {–3, –1, 3, 4, 9, 11} { } {–3, –1, 3, 4, 6, 9, 11, 12, 15}
@ganeshie8 Do you know anything about this?
The set D would be {3, 6, 9, 12, 15 }
Now the union ∪ is going to be all elements from set B and D, without counting common elements twice.
What ok so what your saying is that its B or D because of the negative numbers correct?
Um I'm not sure what you mean. But here is the distinction between \(\cup\) and \(\cap\):Say you have two sets \(A=\{-5, -2, 0, e, 1.9,\frac{31}{3}\}, B=\{-2, 0, 1.9,7,32\}\) \(A\cap B=\{ -2,0,1.9\}\), choose only the elements common in both sets \(A \cup B=\{ -5,-2,0,e,1.9,7,\frac{31}{3},32\}\), choose all elements from both sets (without counting common ones two times)
So can you figure out the answer in your problem?
So sorry man im totally lost in this subject just need to get through because im 4 weeks behind in work.
my guess would be B
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