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Algebra 15 Online
OpenStudy (anonymous):

6. Find B ∪ D. B: {–3, –1, 3, 4, 9, 11} D: {numbers divisible by 3 from 1 to 15} (1 point) {3, 9} {–3, –1, 3, 4, 9, 11} { } {–3, –1, 3, 4, 6, 9, 11, 12, 15}

OpenStudy (anonymous):

@ganeshie8 Do you know anything about this?

OpenStudy (kirbykirby):

The set D would be {3, 6, 9, 12, 15 }

OpenStudy (kirbykirby):

Now the union ∪ is going to be all elements from set B and D, without counting common elements twice.

OpenStudy (anonymous):

What ok so what your saying is that its B or D because of the negative numbers correct?

OpenStudy (kirbykirby):

Um I'm not sure what you mean. But here is the distinction between \(\cup\) and \(\cap\):Say you have two sets \(A=\{-5, -2, 0, e, 1.9,\frac{31}{3}\}, B=\{-2, 0, 1.9,7,32\}\) \(A\cap B=\{ -2,0,1.9\}\), choose only the elements common in both sets \(A \cup B=\{ -5,-2,0,e,1.9,7,\frac{31}{3},32\}\), choose all elements from both sets (without counting common ones two times)

OpenStudy (kirbykirby):

So can you figure out the answer in your problem?

OpenStudy (anonymous):

So sorry man im totally lost in this subject just need to get through because im 4 weeks behind in work.

OpenStudy (anonymous):

my guess would be B

OpenStudy (kirbykirby):

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OpenStudy (kirbykirby):

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