Help! Medal and Fan, if you can help! solve: f(t)=20+150*ln(8t+1) and I have to find 10 minutes, which will then give me the equation f(10)=20+150*ln(8(10)+1) Can someone help solve it?
@YanaSidlinskiy This is the one!
Aww...What a problem..
Yeah! I got f(10)=170*ln(81) but then i'm stuck and i don't even know if it's right..
or at least it should be 20+150*ln(81)... but still stuck on what i should do
ln= ? ? What do you mean?
f(10)=170*ln(81)
That's how far I got, but i need to get the temp.
@phi Can you help?
@AccessDenied, can you help with this?
Or someone -.- @mathmale ?
@whpalmer4 ?
\[ f(t)=20+150*\ln(8t+1)\] \[f(10) = 20+150*\ln(8(10)+1)\]\[f(10) = 20+150*\ln(81)\]
@whpalmer4 yes, i got to that part but can't i solve to get one number? I need to find the temp (f(t))
So don't you have a calculator?
No, actually...
Or select values of \(\ln x\) committed to memory? :-) \[\ln 3 \approx 1.09861\]so \[\ln 81 = \ln 3^4 = 4\ln 3 \approx 4*1.09861 \approx 4.394\]
I've tried wolframalpha, that isn't working... But i'll try the other one. Thanks
Ah... Okay. Thanks for answering! :)
actually, it's the other one that isn't working now :-)
if you just go to google.com and type your expressions into the search box, that usually works, too. https://www.google.com/#q=ln+81
I haven't tried the other one yet... I put it in wrong in wolfram, that's why i couldn't get any answer.
wolfram would probably interpret your problem almost directly: http://www.wolframalpha.com/input/?i=f(t)%3D20%2B150*ln(8t%2B1)+with+t%3D10
This is awesome help! I'm looking through it now :D Thanks !!
it's a great tool, but resist the temptation to have it do your homework!
Lol, yup. Got you.. That's why I come here to get help so i can work with and understand it
Find the interquartile range of the data. A. 6 B. 8 C. 9 D. 20
@natedog12 do not post your questions in someone else's question!
dude that was 30 minutes ago
Doesn't matter, just don't do it.
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