Question

The perimeter of a rectangle is 256 inches. How long are the sides if the length exceeds the width by 16 inches?

Mark lets x represent the width of the rectangle and writes the equation 2x + 2(x + 16) = 256. Solving for x, the width of the rectangle is
A.56
B.60
C.68

Answer 1

I ignored the equation.

56+16=72

72+72+56+56=256

Answer 2

I'm not good with equations, so I just worked with the numbers until I found the answer. Maybe DemolisionWolf will show you the right way to do it.

Answer 3

solve this:
2x + 2(x + 16) = 256

so, first step is use the Distributive Law
2x + 2x + 32 = 256

next, combine like terms
4x + 32 = 256

next, isolate x
4x + 32 -32 = 256 -32
4x = 224
4x/4 = 224/4
x= 224/4

Answer 4

X=56

Answer 5

Yes.

Answer 6

Length: 72
Width: 56

Answer 7

^_^