Question

solve the triangle

Answer 1

Solve the triangle.

A = 50°, b = 13, c = 6

Answer 2

Would it be like a/sin29= 6/sinc

Answer 3

yes but that comes later,
first find the side \(\large a\) using cosine law

Answer 4

you mean pathagrum therm?

Answer 5

this is not a right triangle to apply pythagorean theorem

Answer 6

cosine law :

\(\large a^2 = b^2 + c^2 - 2bc\cos(A)\)

Answer 7

looks familiar ?

Answer 8

not at all c:
but is this right? 6^2 +13^2 -2(6)(13)cos(50)

Answer 9

Looks perfect !

Answer 10

dont forget, that quantity equals \(\large a^2\),
so u need to take square root of that to get \(\large a\)

Answer 11

wait what .-.

Answer 12

a^2 = 6^2 +13^2 -2(6)(13)cos(50)

Answer 13

http://www.wolframalpha.com/input/?i=a%5E2+%3D+6%5E2+%2B13%5E2+-2%286%29%2813%29cos%2850%29

Answer 14

okay i got 54.465

Answer 15

\(\large a = 10.234\)

Answer 16

but... my calculator said 54.465...

Answer 17

burn ur calculator... trust wolfram :)

Answer 18

check if you're in radians mode..

Answer 19

0.0 but that website dosent even tell you the answer! where are you finding 10.234 anywhere on there?

Answer 20

scroll down to the last,
and click on "Approximate forms"

Answer 21

oh c: okay thank you

Answer 22

so you have all the sides...
next apply sine law to find the second angle