Question

could someone put the work into complete sentences for me? I don't know how id explain it
pleasee

a_15=3+3(14)
a_15=3+42
a_15=45
a_15=2(2)^14
a_15=2(16384)
a_15=32768

Answer 1

What are you trying to explain?

Answer 2

the work that was done.. just the process but in complete sentences

Answer 3

it looks like you have 2 formulas: one arithmetic and one geometric

Answer 4

both are finding the 15th term

Answer 5

yes! @jim_thompson5910

Answer 6

so let's focus on the arithmetic sequence

Answer 7

the general formula is

an = a1 + d(n-1)

where

an = nth term
a1 = first term
d = common difference
n = term number

Answer 8

a_15=3+3(14) is the same as a_15=3+3(15-1), so we can see

first term: a1 = 3
common difference: d = 3
term number: n = 15

Answer 9

we plug those values into an = a1 + d(n-1) and evaluate


an = a1 + d(n-1)

a15 = 3 + 3(15-1) ... plug in a1 = 3, d = 3, n = 15

a15 = 3 + 3(14) ... subtract

a15 = 3 + 42 ... multiply

a15 = 45 ... add


After you've done those substitutions, you're just using PEMDAS to evaluate

Answer 10

that's all I have to say for it then?

Answer 11

there's not much to say really since it's just arithmetic after you plug in those values

Answer 12

you'd have more to say about the starting term and common difference if anything

Answer 13

ah! sweet! thanks.
so what should I be saying about them?

Answer 14

I doubt your teacher cares about the arithmetic (in terms of verbal descriptions) just as long as you get the math right you should be fine

so you should be talking about the first term and common difference

Answer 15

basically tell where the sequence starts and how it progresses

Answer 16

In this case, it starts at 3 and it progresses by adding 3 to each term to get the next one

Answer 17

okay, well I have the numbers and all the quiz just asks to be written in complete sentences rather than showing the work

Answer 18

that will lead to the arithmetic nth term formula

an = a1 + d(n-1)

an = 3 + 3(n-1)

Answer 19

Ok, then you'll have to describe what's going on instead of writing out the formulas

Answer 20

so say you're starting with an nth term formula, you plug in the given values and evaluate/compute the result to get 45

Answer 21

I think there should be a place for the formula though since it kinda speaks for itself

Answer 22

of course,

Answer 23

maybe they want full sentences on top of using the formula?

Answer 24

I guess that could be done. all it tells me is to write the work Id be doing in complete sentences. like I said, I have the formulas, I am just lacking the ability to put what ive done into words

Answer 25

That's what I'd do honestly if I were in your shoes. I think the formula is important enough that it'd be silly to leave it out. It's probably a case where you have to pretend you're explaining this to a friend or something.

Answer 26

I guess you could integrate the lines I wrote out into a big paragraph like this maybe


We start with the formula an = a1 + d(n-1) and plug in the first term a1 = 3 and common difference d = 3 to get an = 3 + 3(n-1). This is the nth term formula for the given sequence with starting term 3 and common difference 3. To find the 15th term, we plug in n = 15 and evaluate. So a15 = 3 + 3(15-1) = 3+4(14) = 3+42 = 45 is the 15th term of the arithmetic sequence.


Something along those lines. That might be what they are aiming for.

Answer 27

thank you so so much!

Answer 28

you're welcome

Answer 29

would you be able to help me on the last one that I also solved and has to be written?

Answer 30

are you able to get started on it?

Answer 31

on the paragraph?

Answer 32

yes, what kind of sequence does that formula deal with?

Answer 33

its pretty much the same thing but with a higher number

Answer 34

ok what else

Answer 35

I have the work solved. want to see that?

Answer 36

I see it at the top (unless you have more work that's not posted?)

Answer 37

yeah, its a different problem I did

Answer 38

ok go ahead and post it

Answer 39

a_20=3+3(19)
a_20=3+57
a_20=60
a_20=2(2)^19
a_20=2(524288)
a_20=1,048,576

Answer 40

oh I'm guessing you already wrote the paragraph for

a_15=2(2)^14
a_15=2(16384)
a_15=32768

Answer 41

yes

Answer 42

ok great

Answer 43

the first part

a_20=3+3(19)
a_20=3+57
a_20=60

will follow the same format because this is also an arithmetic sequence (in fact, it has the same starting term 3 and common difference 3, so it's the same sequence)

Answer 44

the only difference this time is we're finding the 20th term instead of the 15th

Answer 45

as for

a_20=2(2)^19
a_20=2(524288)
a_20=1,048,576

this is a geometric sequence with first term of 2 and common ratio of 2 (we're finding the 20th term here too)

Answer 46

okay, great. I think I know where to go from there then

Answer 47

alright, I'm glad it's clicking now

Answer 48

me too! :D I really appreciate your help!

Answer 49

I'm glad I could help