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OpenStudy (alina123):
OpenStudy (e.mccormick):
\(\dfrac{\text{Lengths on Drawing/Map}}{\text{Length in Real World}}=\text{scale ratio}\)
OpenStudy (alina123):
so c
OpenStudy (e.mccormick):
Well, depends on what it simplifies to. I did not do the math.
OpenStudy (e.mccormick):
Yep. Looks like it simplidies to that.
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OpenStudy (alina123):
ok
OpenStudy (alina123):
the next question
OpenStudy (e.mccormick):
OK, what do you need to find an area? Once you know that, then you know what you need to find.
OpenStudy (alina123):
l times w
OpenStudy (e.mccormick):
So your answers are all in inches. That means you need the L and W in inches. So, understand how you would get that using the scale?
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OpenStudy (alina123):
oh ok
OpenStudy (alina123):
so 16in
OpenStudy (e.mccormick):
=)
OpenStudy (alina123):
on to number 3
OpenStudy (e.mccormick):
OK. So, have any ideas there?
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OpenStudy (alina123):
with the other dimensions do something with the scale or the first deminsions
OpenStudy (e.mccormick):
Yes. You have both inches and miles on both maps. So, the miles in the real world are going to be the same. What is changing is the inches of the map. What scale do they change by?
OpenStudy (alina123):
A
OpenStudy (e.mccormick):
.5 to 4 on small vs .25 to 4 on large means that the larger map would cover more area. It has more inches and each inch would represent more miles.
OpenStudy (alina123):
can you explain that in depth
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