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what is the phase shift of h(t)=-2cos(5t-pi/7)
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A wave is described by an equation in the form of: \[y(t) = Acos(\omega t - \phi)\] where \[A = Amplitude, \omega = Angular Frequency, \phi = Phase Shift\]
You can also switch in a sin for the cos. The only thing that'll change is the phase shift. But you should be able to pick out the phase shift easily.
it does not do throw in my my homework system
i entered pi/7
do i have change the sign or something???
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Oh, I completely blanked on something. We need to get the function into a slightly different form: \[y = A \cos (\omega t - \phi) \rightarrow A \cos(\omega(t - \frac{\phi}{\omega}))\] Your phase shift would then be phi/omega
thank you i got it
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