help please! sum of a geometric series!! word problem
Diana received 65 points on a project for school. She can make changes and receive three-tenths of the missing points back. She can make as many corrections as she wants. Create the formula for the sum of this geometric series and explain your steps in solving for the maximum grade Diana can receive. Identify this as converging or diverging.
Well I need to know the full mark or I wouldn't be able to know the missing points
the full mark?
Is it 100?
that is all the problem, i believe the common ratio is 3/10 and the a1=65
i dont know what you mean with full mark
Well the question is asking "three-tenth of the MISSING points"...
dianna recived 65 points on the project so the missing points would be 35
a1 is indeed 65 but the common ratio wouldn't be 3/10
it wouldn't?
Or else it would be "the new mark is three-tenths of the original mark"
Maybe write a recurring formula first? In order to know what's going on?
i dont remember what the recrusive formula was, i belieb it was an = a1(r)^(n-1) ?
Not "the" recursive formula, "a" recursive formula
Recursive formula is expressing the next term in terms of the previous
So in this case the next term would be the previous plus three-tenths of the missing points
\[\Large a_{n+1}=a_n+\frac3{10}(100-a_n)\]
yes i was typing that
Simplify this
an+1 though?
ok 1 sec
\(\Large a_{n+1}\) is the next term while \(\Large a_n\) is the original
shouldnt you have to substitute 65 for n?
or an int his case
No, 65 is \(a_1\)
So simplify it and we'd get: \[\Large a_{n+1}=0.7a_n+30\]
So this isn't a geometric sequence at all
no, it series
This isn't geometric at all
Geometric (series/sequence) wouldn't have +30 in the recursive formula
ohhh I'm starting to think its arithmetic not geometric, geometric is what the word problem says it is, maybe with the equation \[65+\frac{ 3 }{ 10 }(2-1)\]
Arithmetic wouldn't have the multiplier 0.7
equal to an or a2 in this case, since n=2
I'm wondering whether "missing points" really means the distance between the mark to the full mark
And what you wrote ain't a formula at all
yes, missing points are 35, the distance between 65, her grade, the full mark, which is 100
to* the full mark
It's neither arithmetic nor geometric
The formula of a typical arithmetic sequence would be \(\Large a_{n+1}=a_n+18\) The formula of a typical geometric sequence would be \(\Large a_{n+1}=18a_n\)
maybe they want me to write a sigma notation?
So it's neither arithmetic nor geometric
im guessing is not, i thought it was geometric series because the problem said so but now think is sigma notation what they want
\[\sum_{n=1}^{\infty}\]
What I wrote was just the recursive formula, sigma notation requires the explicit formula
i see
maybe \[65 +\frac{ 3 }{ 10 }(n-1)\]
What's n?
So \(a_2\) would be 65.3?
according to your formula?
n is would be 2 in this case. we would get \[\sum_{n=1}^{\infty}\frac{ 3 }{ 10 }n -0.3\] i believe
yes
the problem asks to create a formula, but i dont know if i am right or not
I have absolutely no idea how you got your formula
the formula originates from an=a1+d(n-1)
So you already assumed that it's arithmetic
yes arithmetic, but written in sigma notation, I'm not sure tho, i suck at word problems, theyre my weakness
It's not arithmetic at all
then i dont know, im confuse
Oh man this question is trolling you
It's neither arithmetic nor geometric
its a convergent sigma. but thanks for leaving man, appreciate the hard work.
i believe the formula is \[sn = \frac{ a1 }{ 1-r }\]
the formula im trying to get with this is
Man, this is the formula for a geometric series
The sequence in question is NEITHER arithmetic NOR geometric
This is geometric.
\[\sum_{i=1}^{\infty}a1(r)^{i-1}\]
i knew! lol
is my guess right or wrong...?
@tHe_FiZiCx99 How so?
becaus 3/10 is being multiplied to the "missing" points and then being added to a1 which is 65, i believe thats why
If it involves the "missing" points it can't possibly be geometric...
I'm going to try and make sense in this, I only have a few minutes left. 100 - 65 = 35 (assuming this is 100) she lost 35 points, she can get 3/10 of those points back '35' is the missing point * \(\ \dfrac{3}{10} \) = \(\ \dfrac{35 * 3}{1 * 10} = \dfrac{105}{10} = 10.5 \) 65 + 10.5 = 75.5
so if i were to write an equation for it would this be right? \[\sum_{i=1}^{\infty}a1r ^{i-1} = \sum_{i=1}^{\infty}64(\frac{ 3 }{ 10 })^{i-1}\]
65*
a thought, it's converging at 75.5, the formula I would use is; s = 65 + 3/10*n
Well, I have to get off it's midnight for me! Bye!
same here:/
Good luck :>
come on mate, east coast:)? i need help, its a final test..
its my last question before sleep
well he was right about the 75.5, but i don't know how the equation would look
@wio can you give us a hand mate?
or want me to open a new question?
The question is confusing.
the questions quotes lesson 8.6 in my class, which is sigma notations. convergent and divergent. i know its geometric and i know its convergent because the ratio is 3/10
So she starts with \(a_1 = 100-64= 36\) missing points... and each time she can get \(3/10\)ths of them back?
yes
she has 65 and each time she gets 3/10ths of 35(missing points) back
a1=65 r=3/10 i believe this is right..?
Wouldn't her highest score be if she doesn't miss anything on the first correction?
Or does she get to correct the same question twice in a row?
yes, the first time she missed something, and she got a 65/100, she is resubmitting to gain back 3/10ths of the missing points, 35
she is able to resubmit as many times as she wants
Well, if she submits infinite times then she will get back to 100.
But I'm confused about what we are supposed to be expressing as a geometric series.
i think we are supposed to be expressing as a convergent, sigma notation..?
the problem is that it isn't an actual geometric series.
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