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OpenStudy (anonymous):
What is the molarity of 250 mL solution containing 2 moles of Al(NO3)3?
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OpenStudy (anonymous):
Molarity = moles / Volume in Liter !st convet 250 ml tp L by dividing with 1000 t.e 0.25 L now M = 2 / 0.25 = 8 M is the molarity of Al(NO3)3
OpenStudy (anonymous):
thanks i understand
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