The summit of a mountain,2450m above base camp,is measured on a map to be 4580m horizontally from thecamp in a direction 38.4°west of north.What are the compo-nents of the displacement vector from camp to summit?What is its magnitude?Choose the x axis east, y axis north,and z axis up
you already know the z axis component do you know how to resolve the 4580 m into north and east components?
i think the question is badly worded. my first impression was that the 4850m horizontally was to be used as the x axis component
4850 horizontally is sqrt(x^2+y^2)
so is 4850m the hypotenuse of the right triangle formed from the x-axis and y-axis?
yes
ok based on that logic then the x axis component is -2450m, the y axis component is 3870m, the z axis component (given) is 2450m
I thought the question implied that the 4850m was the x axis component because it says the summit of the mountain is 4850m "horizontally" It is badly worded
horizontally = not vertically
there are two horizontal dimensions
but your error is understandable, I think I made that once or twice myself
so the final magnitude is what?
oh okay thanks, then the problem should really say "diagonally". i thought i was the only one with that logic when i approached the problem.
the magnitude comes out to 5190m as the displacement vector to the summit from camp
about that, yes. good job.
thanks for the help :)
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