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Mathematics 14 Online
OpenStudy (anonymous):

The summit of a mountain,2450m above base camp,is measured on a map to be 4580m horizontally from thecamp in a direction 38.4°west of north.What are the compo-nents of the displacement vector from camp to summit?What is its magnitude?Choose the x axis east, y axis north,and z axis up

OpenStudy (anonymous):

you already know the z axis component do you know how to resolve the 4580 m into north and east components?

OpenStudy (anonymous):

i think the question is badly worded. my first impression was that the 4850m horizontally was to be used as the x axis component

OpenStudy (anonymous):

4850 horizontally is sqrt(x^2+y^2)

OpenStudy (anonymous):

so is 4850m the hypotenuse of the right triangle formed from the x-axis and y-axis?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok based on that logic then the x axis component is -2450m, the y axis component is 3870m, the z axis component (given) is 2450m

OpenStudy (anonymous):

I thought the question implied that the 4850m was the x axis component because it says the summit of the mountain is 4850m "horizontally" It is badly worded

OpenStudy (anonymous):

horizontally = not vertically

OpenStudy (anonymous):

there are two horizontal dimensions

OpenStudy (anonymous):

but your error is understandable, I think I made that once or twice myself

OpenStudy (anonymous):

so the final magnitude is what?

OpenStudy (anonymous):

oh okay thanks, then the problem should really say "diagonally". i thought i was the only one with that logic when i approached the problem.

OpenStudy (anonymous):

the magnitude comes out to 5190m as the displacement vector to the summit from camp

OpenStudy (anonymous):

about that, yes. good job.

OpenStudy (anonymous):

thanks for the help :)

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