If the length of each side of a cube is reduced to one-third its original value, is the surface area reduced to one-third its original value? Use an example to support your answer.

Question

anonymous · Answer

finally i got the answer :P

wolf1728 · Answer

Volume of a cube = (side)^3
Surface area of a cube = (side)^2 * 6
So, if we reduce one side to one third, then the surface area becomes 
(1/3)^2 * 6
(1/9) * 6
Original area = (1) * 6
New area = (1/9) * 6
So if we reduce one side to a third then the surface area is reduced to 1/9 of that it was originally.
(Although you didn't ask this, when a side is reduced to 1/3 then the volume decreases by 1/27)