Question

find two geometric means between 486 and 6

Answer 1

Multiply them and take the square root of the result.

Answer 2

if b is the geometric mean between a and c , then
\(\large b^2 = ac \\ \large b = \sqrt {ac}\)

Answer 3

let G1 and G2 be two G>means between 486 and 6
then 6 , G1 , G2 , 486 are in G.P
1st term = 6
last or 6th term = 486
and n =4
G1 =a*r
G2 = a*r^2
you have already first term you have to just find common ratio 'r'