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Mathematics 7 Online
OpenStudy (anonymous):

Question about the substitution method. Medals! I was wondering why taking the first and second step remove 3(t)^2 by taking the derivative. Does 6t just turn into an arbitrary constant thereby negating itself?

OpenStudy (anonymous):

OpenStudy (anonymous):

as opposed to

OpenStudy (anonymous):

\[(t ^{3}+4)=u \] \[then\] \[du/dt=3t ^{2}\] now \[du=3t ^{2}dt\] then replace the values and do normal integration.. hope it will help you.. thank you..

OpenStudy (anonymous):

2nd one try in same way.. if you dont understand then tell me..

OpenStudy (anonymous):

but after du=3t^2 it disappears, is that because it becomes a constant? I know that the u^5 becomes u^6/6 but I can't see you du would fit in.

OpenStudy (anonymous):

no actually (t) is a variable.. and we replacing it by another variable for the shake of easy calculation.. its not a constant..

OpenStudy (anonymous):

replacing t with d(u) which is a dummy variable, what about the second question with sqrt(4x-5) why does the dummy variable = (1/4)du when for 3t^2 neq 6du

OpenStudy (anonymous):

while for*

OpenStudy (anonymous):

hang on for one minute...

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

OpenStudy (anonymous):

is it helful or not?

OpenStudy (anonymous):

very helpful, really helps to see it on paper. thanks so much (:

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