Question

Write an equation of the hyperbola with vertices at (6,-3)(6,1) and foci at (6,-6)(6,4)

Answer 1

@ganeshie8 so i solved this o ut and for my final answer i got (x-6)^2/16-(y+2)^2/12=1

Answer 2

the center is (6,-1) a=4, c=2? opens up and down

Answer 3

it is a vertical hyperbola right ?

Answer 4

so y^2 term must come first

Answer 5

ok

Answer 6

\(\large \dfrac{(y-(-1))^2}{a^2} - \dfrac{(x-h)^2}{b^2} = 1\)

Answer 7

\(\large a\) = distance between center and vertex
= 1 - -1
= 2

Answer 8

right ?