Question

1+sinx+sin^2x+sin^3x+.... = 4+2√3
Solve for x

Answer 1

\[1+sinx+\sin^2x+\sin^3x+.... = 4+2√3\]

Answer 2

0<x<pi, x is not equal to pi/2
then find x

Answer 3

do you find any pattern in that infinite series ?
hint : geometric sequence

Answer 4

OMG! :P That just didn't strike me! Shoot!
Lemme try that!

Answer 5

hey @hartnn , just one thing.. shall i take 1 as the first term of sinx ..
I mean, 1/sinx = r if 1 =a and
r=sinx if a=sinx

Answer 6

a is the first term of the sequence.
here, first term = 1
so a = 1

Answer 7

r= sin x

Answer 8

so you should get
\(\large \dfrac{1}{1-\sin x} = 4+2\sqrt3\)

solve this for sin x