Solid ammonium nitrate decomposes explosively to form nitrogen gas,
oxygen gas, and water vapor. Assume 100% yield.

How many moles and grams of each of the three products are produced when 3.00 g of ammonium
nitrate decomposes?

I already solved for the mol of the 3.00g of Ammonium Nitrate but how do I solve for the moles and grams of each product produced?

Question

Solid ammonium nitrate decomposes explosively to form nitrogen gas, 
oxygen gas, and water vapor. Assume 100% yield.

How many moles and grams of each of the three products are produced when 3.00 g of ammonium 
nitrate decomposes? 

I already solved for the mol of the 3.00g of Ammonium Nitrate but how do I solve for the moles and grams of each product produced?

gebooors · Answer

You need equation for reaction.

gebooors · Answer

NH4NO3 -> N2 + O2 + H2O
Can you balance this?

gebooors · Answer

I think it is 2 NH4NO3. -> 2 N2 + 1 O2 + 4 H2O

gebooors · Answer

Number of moles of N2 is same as NH4NO3.
Thus m(N2)= n * M

elleblythe · Answer

what do you mean by "m(N2)= n* M??? @Gebooors