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Mathematics 7 Online
OpenStudy (anonymous):

On Peter's summer vacation, he kayaked 1.0 × 106 meters down the Mississippi River. He paddled at a rate of 6.0 × 103 meters per hour. How many hours did he paddle on the river to complete his trip? Round your answer to the nearest 10.

OpenStudy (anonymous):

I did?

OpenStudy (anonymous):

Well, distance is equal to rate times time. So just plug in, I suppose ^.^

OpenStudy (yanasidlinskiy):

Peter kayaked 1.0 x 10^6 meters at a rate of 6.0 x 10^3 meters per hour. That's the scientific expression.

OpenStudy (yanasidlinskiy):

The number of hours Peter paddled is \[\frac{ 1\times 10^6 }{ 6 \times 10^3 }\]=\[\frac{ 10 \times 10^5 }{ 6 \times 10^3 }=(\frac{ 10 }{ 6 }) \times 10^2=(\frac{ 5 }{ 3 }) \times 10^2 = 1.7 \times 10^2 = 170\]

OpenStudy (anonymous):

How incredibly tiresome :D

OpenStudy (yanasidlinskiy):

Yea.! I know! I just tried my best!:)

OpenStudy (anonymous):

No, I meant rowing for a hundred and seventy hours. Who does that? (Except me, apparently XD )

OpenStudy (yanasidlinskiy):

Oh...yea...ok...That's crazy!:) lol... I think they got pretty tired!:) lol...

OpenStudy (anonymous):

The original asker isn't here anymore. Well-played, anyway ^.^

OpenStudy (yanasidlinskiy):

>_< ------- love this expression:) anyways..

OpenStudy (anonymous):

You still 'cheated', though. :P 170 is a few hours too many XD I'ts more like 166.6666666... ^.^ anywaaaay...

OpenStudy (yanasidlinskiy):

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