Question

How should I proceed to integrate this:

Answer 1

where's the question?

Answer 2

He's getting there

Answer 3

@hartnn @GabbyCakes @Mel98 @bringmethehorizon

Answer 4

\[\large \int\limits \dfrac{\sec x \;dx}{\sqrt{\cos 2x}}\]

Answer 5

@ElvenBlackout

Answer 6

@mathmale

Answer 7

Why is this becoming a tagging party? :O

Answer 8

I'd start by re-writing sec in sin and cos

Answer 9

Let's just wait for someone to come up with a solution ;)

Answer 10

Start by calling your alien friends, as they are a more developed race. especially more developed than an 8th grader like me. (AKA: I can't help you. I have no stinkin idea.)

Answer 11

then use a double angle identity

Answer 12

@FibonacciChick666 But which form should I express cos 2x?

Answer 13

@BlazeBeat Calling all autobots :)

Answer 14

the sin^2 one

Answer 15

I can't see the mathematical form of your integral - could you please use the equation function?

Answer 16

@AravindG Autobots- Roll out!

Answer 17

1-2sin^2x

Answer 18

k lemme try it on paper.

Answer 19

yea, then use u sub

Answer 20

OK ...

Answer 21

@shiraz14 I used the equation editor above.

Answer 22

That's strange - all I see is code ...

Answer 23

wait, that won't work... I think you'll run into a wall with the derivative

Answer 24

ari- just wondering- did you watch any of transformers prime series?

Answer 25

\[\dfrac{dx}{\cos x(\sqrt{1-2\sin^2 x})}\]

Answer 26

Yeah thats what I landed on when I tried your method @FibonacciChick666

Answer 27

@BlazeBeat All of them :P

Answer 28

hmm have you had complex variables?

Answer 29

@moonlight123

Answer 30

Ok, now I see the integral - its' a fault with my browser ... :p

Answer 31

I don't think it's too complex for that. Then answer looks simple. I am missing out the method of attack.

Wolf has the answer https://www.wolframalpha.com/input/?i=int+%28sec+x+dx%29%2F%28sqrt%7Bcos+2x%7D%29

Answer 32

@AravindG I hated how it ended. optimus had to die D:
but bumblebee got to kill megatron, died right after, but got to talk again after!!!

Answer 33

ooh wait! just let u= cos2x

Answer 34

then you can cancel stuff

Answer 35

@BlazeBeat Let's discuss it in pm later. For now back to question :)

Answer 36

@AravindG aye aye cap'n

Answer 37

u=cos 2x
That leaves me with
du=-2sin 2xdx

Answer 38

yes, so now, you need to get the same theta

Answer 39

Have you tried using u = cosx?

Answer 40

Then convert cos2x into 2 cos^2(x) - 1 = 2u^2-1

Answer 41

But then how will you express dx in terms of u?

Answer 42

du=-sinx dx then they cancel

Answer 43

use sinx/sinx, that would probably work

Answer 44

sinx = square root [1-cos^2 (x)]

Answer 45

hmm.. Sorry but I am not able to follow. Could u show the steps you are trying to tell me?

Answer 46

yea, I think this is what he's getting at let u=cosx du=-sinx dx

Answer 47

But there is no sin x on numerator?

Answer 48

\[dx = - \frac{ 1 }{ \sqrt{1-u^{2}} } du\]

Answer 49

\[\int\frac{1}{sinx(2cos^2 x-1)^{.5}} dx\]

Answer 50

brb class

Answer 51

okay let me try that @shiraz14

Answer 52

0_0 im in geometry and i just read this whole thing.....

Answer 53

lol ^

Answer 54

and i just kept getting more and more confused

Answer 55

@shiraz14 By your method I reached a more complex looking integral.

Answer 56

@hartnn , @AccessDenied any inputs?

Answer 57

I was going to try a Weierstrass sub just for funsies, just woke up so i'll see what happens there. lol

Answer 58

@AravindG do u really need help or do mods at 99 just like posting really really difficult questions

Answer 59

I can wait lol.

Answer 60

@..... Not really. Mods are just normal people like with their own life and things to study. This qn came up when I was doing a practice session.

Answer 61

I am sure the question isn' t as difficult as it seems to be. We are missing an important starting step. @ganeshie8 ?

Answer 62

isnt as difficult as it seems to be..... it has more letters and symbols than numbers

Answer 63

:'( what class is this

Answer 64

The integral may look complex at first, but it simplifies nicely into the following:

\[-\int\limits_{?}^{?}[u ^{2}(2u ^{2}-1)(1-u ^{2})]^{-1/2} du\]

Answer 65

0_0^

Answer 66

Yeah I got something like that What do u do with it? So many terms in the denominator?

Answer 67

@..... LOL

Answer 68

its funny cause shiraz said it all looks like code to me.....same here shiraz

Answer 69

LOL ... that was my browser because it wasn't working ... :)

Answer 70

In short that didn't lead anywhere nice. [[ plain text work http://www.texpaste.com/n/1x7wft9n ]]
will keep looking here.

Answer 71

tanx/2 would help.

Answer 72

@Abhishek619 Could you elaborate?

Answer 73

plz do