Question

A block of mass 1.5 kg slides down an inclined plane that has an angle of 15. If the inclined plane has no friction and the block starts at a height of 3 m, how much kinetic energy does the block have when it reaches the bottom? Acceleration due to gravity is g = 9.8 m/s2.

Answer 1

Calculate acceleration in inclined plane. Because there is no friction,
F = ma = mgsin 15.

Then calculate distance s which mass moves in inclined
Plane.

Then s = 0,5 at^2 you can solve time t.
Then calculate final speed v = at and
Kinetic energy

Answer 2

Alternatively, gain in kinetic energy = (1/2) m v^2 = m g h.