Question

.

Answer 1

Is this calculus?

Answer 2

@poiuyt1234 If you would like help, I will help you! But if you don't answer what I asked..

Answer 3

Ok. Here we go!:)

Answer 4

If we have P of something, and it grows 10% in one year we would write an equation that looks like this
y = 10% * P
Or changing 10% to 0.1
y=P+0.1P
\[y=(1+0.1)P\]
if it grows another 10% the next year, we would write
\[y=((1+0.1)P)) \times (1+0.1)\]
\[y=(1+0.1)^2P\]
in n years
\[y=(1+0)^nP\]

Answer 5

Sorry took a little while.

Answer 6

notice that 10% growth means (1.1)^x
if we had 0.9 instead of 1.1, instead of growing, P would get smaller
\[y=0.9P=(1-0.1)P=P-0.1P=P-10%P\]
0.9 means it decreases by 10% each year.
For your problem, I would change 0.82 to 1 + some number
then change the "some number" to a percent