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Write as a sum of partial fractions. x/(3x-2)(2x+1)
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\(\large \dfrac{1}{(ax+b)(cx+d)}=\dfrac{A}{ax+b}+\dfrac{B}{cx+d}\)
so is it A/(2x+1) + B/(3x-2) ?
thats absolutely correct :)
do you also need to find values of A and B ?
Yes - substitute x=2/3 and x=-0.5 in the original equation to find A & B.
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You'll have to do this one at a time.
when you do that is one A and one B?
yes, to get the value of A, you put x =-1/2 to get the value of B, you put x= 2/3
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