Question

What are the solutions to the Quadratic Equation?
2x^2-16x+32=0

Answer 1

factor out the '2' first.

Answer 2

\[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ }\]
a = 2
b = -16
c = 32

Answer 3

sorry here's the eqation, forgot to type in "2a"

Answer 4

\[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]

Answer 5

if you plug in the values of a, b and c, you should be able to get a fairly simple equation out of that ^.^

Answer 6

factor method will be easier than using the formula

Answer 7

well can you help? im confused. it said to use the formula

Answer 8

@hartnn
factoring is easier when its an expression, not an equation

Answer 9

Yes, I'll help :)

Answer 10

factor out of 22, complete the square !

Answer 11

out of 2 I mean

Answer 12

if it explicitly mentions to use formula, then follow what jade says :)

Answer 13

@SolomonZelman i hate completing the square. lol it makes me confused

Answer 14

dang...

Answer 15

That made me feel smart >.<

Answer 16

Glad that jadeishere is able to help. Note that we could have gotten started out faster had you included all of the instructions (use the quadratic formula).

Answer 17

@ShelbyRenaebb , actually, it is very good, you just have to know when to use it and when not to.

Answer 18

Okay, instead of discussing what is easier, can we help? Sorry if that sounds rude :O

Answer 19

helpppp

Answer 20

So in using the quadratic formula, once you plug in the values, it will look like this
\[x = \frac{ -(-16)\pm \sqrt{(-16)^2 - 4(2)(32)} }{ 2(2) }\]

Answer 21

i have five problems i dont know how to do D:

Answer 22

shelby, at any point if you don't understand something, do ask doubts

Answer 23

A negative multiplied by a negative equals a positive. Meaning -16 will then turn into +16.
We'll work on this one first. I'll help with any that I know. :)

Answer 24

2x^2-16x+32=0 can be done immediately with the quadratic formula, if that's what we're supposed to use to solve it.

Then, as someone else has already pointed out, a=a, b=-16 and c=32.

Plugging these values into the quadratic formula (given above):\[x=\frac{ -(-16)\pm \sqrt{((-16)^2-4(2)(32))} }{ 2(2) }\] Shelby, can you take the solution friom here?

Answer 25

Thanks. Just please can we all work together and figure out these five problems? D: I have a test coming up soon and I am studying my study guide and cant figure out these 5 problems

Answer 26

im doing the quad form now

Answer 27

Kay i'll work you through the steps if you need help

Answer 28

for quadratic formula, you first need to find values of a,b,c
are you comfortable with finding these values ?

Answer 29

im working them out now

Answer 30

Hints: -(-16)=16; (-16)^2=256; and (4)(2)(32)=256. Shelby?

Answer 31

i am at x=16+/- sqroot 16128 over 4

Answer 32

\[x = \frac{ 16 \pm \sqrt{256 - 256} }{ 4 }\]

Answer 33

The 16 and the 4 are fine. Please re-examine what you did to obtain Sqrt(16128).

Hint: 256-256=?

Answer 34

wait id be zero

Answer 35

Yep :) did you multiply 256 * 256?

Answer 36

i thought itd be 0

Answer 37

Exactly. 256-256=0. And so your TWO roots are real, equal, and equal to what number?

Answer 38

4?

Answer 39

16-0 / 4 = x and 16 + 0 /4 = x

Answer 40

\[x=\frac{ 16\pm0 }{ 4 }=?\]
Yes! your two real, equal roots are {4,4}.

Answer 41

ya i got 4

Answer 42

What is the solution to this equation? 5x^2=50

Answer 43

Just remember that you really do have 2 roots, because you're solving a 2nd-order equation; your 2 roots happen to be equal.

Answer 44

yep :) really what the quadratic formula is following PEMDAS, in a certain way

Answer 45

Would you mind posting this as a new question? (Relenting.) Since you're short on time, let's move forward. Div. both sides by 2. Try to figure out why we wuld do that>

Answer 46

divide by two??????

Answer 47

he meant divide both sides by 5

Answer 48

lol ok i was like Huhhh?

Answer 49

x^2=10?

Answer 50

yup, now take square root on both sides

Answer 51

... remembering to use the "plus or minus" sign on the right side of your equation. (Sorry about that "divide by 2" blunder.)

Answer 52

Haha its okay, im just glad your helping it means alot. I'm trying to get All A's in my classes :D

Answer 53

so 3.16?

Answer 54

Glad you're happy! It's nice to feel appreciated.\[\sqrt{x^2}\pm \sqrt{10}\]becomes what?

Answer 55

x=square root of 10?????

Answer 56

3.16 is technically correct, but it's much nicer and more accurate to leave your answer in the form\[x=\pm \sqrt{10}\]

Answer 57

Yes, plus or minus the square root of 10. Again, remember, Shelby: you have TWO roots because your equation is a QUADRATIC (2nd order) one.

Answer 58

oh ok good to know i should pretty my ending answer lol (:

Answer 59

Yes, as pretty and ask accurate as possible. We could also color it orange.

Answer 60

Hahaha

Answer 61

Shelby: Why not post your next question, but separately? You're doing fine.

Answer 62

If I hadn't already given my medal to hartnn i'd give you one @mathmale

Answer 63

4x^2-6x-10=0 Solve using Quadratic Formula! I think i can do this one but, can we do it together so i can practice???

Answer 64

Cause its easier on here.

Answer 65

Use the equation we had used before
Can you tell me which numbers are the a, b and c values?

Answer 66

i already did the whole problem pretty much, but i got x = 6 +/- sqroot 196 over 8

Answer 67

Okay let's start over
4x^2-6x-10=0
if the value of a is 4, what are the values of b and c?

Answer 68

i got 2.5,-1

Answer 69

-6 and -10

Answer 70

So plugging those into the formula we get *drumroll*
\[x = \frac{ -(-6) \pm \sqrt{-6^2 - 4(4)(-10)} }{ 8 }\]

Answer 71

\[x = \frac{ 6 \pm \sqrt{36 + 160} }{ 8 }\]

Answer 72

so i was right

Answer 73

Did you have that, at this point?

Answer 74

\[x = \frac{ 6 \pm 14 }{ 8 }\]

Answer 75

yuup!

Answer 76

Haha okay
x = -1 and x = 2.5
Yes, you're right >.< Nice job :)

Answer 77

yay!

Answer 78

Need any more help?

Answer 79

Simplify the imaginary unit i. Square root of -16

Answer 80

okay that requires complex numbers, not my strongest area. @AravindG @beccaboo333

Answer 81

ok ill open it in neww question

Answer 82

Kaykay