Question

PLEASE HELP and ill MEDAL!!Simplify the imaginary unit i. Square root of -16

Answer 1

4i

Answer 2

\[\sqrt{-16}=\sqrt{16*-1}=\sqrt{16}*\sqrt{-1}=4*-1=4i\]

Answer 3

oh thats all u do?

Answer 4

yeah sqrt of -1=i

Answer 5

That's correct @xlovely_Lizardx

Answer 6

oh yeah i remember that! i wrote that in my notes

Answer 7

Mind helping me with one more????

Answer 8

sure :D

Answer 9

\[\sqrt{16}\sqrt{-1}=4\sqrt{-1}=4i\]

Answer 10

-5+i over 2i ...simplify the expression.

Answer 11

hmmm I havn't done imaginary stuff in a few years but if i remember correctly:\[\frac{ -5+i }{ 2i }=\frac{ -5+\sqrt{-1} }{ \sqrt{-2} }=-5+\sqrt{\frac{ -1 }{ -2 }}=-5+\sqrt{\frac{ 1 }{ 2 }}\]

Answer 12

does that look right?

Answer 13

i think..lemme check my work

Answer 14

i have noo idea. @radar do you kknow if this is right?????????

Answer 15

@radar

Answer 16

I'm here (now). Multiply the numerator and denominator by i i/i if 1 and would not change the value of your fraction. this would give you
(-5i + i^2)/2i^2 Do you follow ?

Answer 17

yes i have taht