A can of Coke is supposed to contain, on the average, 16 ounces of soda with a standard deviation of 0.4 ounces. Suspecting fraud, you take a random sample of 50 cans and measure the amount of Coke in each. Your measurements show that the 50 cans had a means 15.9 ounces. What is the probability of a random sample of 50 cans having a mean of 15.9 ounces of soda or less?
is this the 1 you want help on?
yes
alright, lets see what we got...
what grade is this?
12th
alright thanks. I believe we need to find the z score, and use a z table, do you have those
yes
rad, ok, calculate the z score then with the numbers they gave us
calculate 16+50+15.9=71.90
i was thinking this equation \[z = \frac{ x-\upsilon }{ \sigma }\]
x = the mean of sample data set u = the mean of ALL data sigma = the standard deveiation
z=16-71.9/0.4
or is it 16-15.9/0.4
16-15.9/0.4 this one
wait, the 16 and 15.9 are backwards its (15.9-16)/0.4
-24.1
close, in math you have to do ( ) then divide do this first: (15.9-16)
(15.9-16)=-0.1
yep, then do -0.1/0.4
sorry (15.9-16)/0.4=0.25
(15.9-16)/0.4=-0.25
good, now look on your z table and find the value for -0.25
I met -0.25
find the probability by taking you z score value of -0.25 and taking the numbers like this on the graph |dw:1397852474632:dw|
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