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Mathematics 21 Online
OpenStudy (anonymous):

Explain this to me please

OpenStudy (anonymous):

OpenStudy (anonymous):

@hartnn

hartnn (hartnn):

to get 6th term, just plug in n=6 in that equation

OpenStudy (anonymous):

okay i got \[a _{6}= \frac{ 1 }{ 125 } (5_{5})\]

hartnn (hartnn):

you mean 5^5 ? also you forgot the negative

OpenStudy (anonymous):

Yes i meant 5^5

hartnn (hartnn):

and 125 = 5^3 can you simplify the fraction ?

OpenStudy (anonymous):

Im thinking it would be -125

OpenStudy (anonymous):

The answer to the whole problem is -125

hartnn (hartnn):

not actually \(-5^5/5^3 = - 5^{(5-3)} = -5^2 =.... \)

OpenStudy (anonymous):

Ohh duh -25

hartnn (hartnn):

yes!

OpenStudy (anonymous):

Can ou help me with my next one?

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