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Explain this to me please
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@hartnn
to get 6th term, just plug in n=6 in that equation
okay i got \[a _{6}= \frac{ 1 }{ 125 } (5_{5})\]
you mean 5^5 ? also you forgot the negative
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Yes i meant 5^5
and 125 = 5^3 can you simplify the fraction ?
Im thinking it would be -125
The answer to the whole problem is -125
not actually \(-5^5/5^3 = - 5^{(5-3)} = -5^2 =.... \)
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Ohh duh -25
yes!
Can ou help me with my next one?
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