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Algebra 18 Online
OpenStudy (anonymous):

Part A: Factor 3x2y2 - xy2 - 2y2. Show your work. (3 points) Part B: Factor x2 + 6x + 9. Show your work. (3 points) Part C: Factor x2 - 25. Show your work. (2 points) Part D: Do the polynomials in parts A, B, and C have a common factor? Explain your answer. (2 points) HELPPP WITH ALLLL OF THIS AND SHOWINGG THE WORK PLEASEEEEEEEE TOO HELPP MEEE GET CREDIT :) :)

OpenStudy (anonymous):

@Guyzrc00l

OpenStudy (anonymous):

Could you show where the numbers are exponents? So we didn't do any mistakes.

OpenStudy (anonymous):

@Guyzrc00l OKAY.

OpenStudy (campbell_st):

well for the 1st question remove the common factor \[y^2(3x^2 - x - 2)\] now you need to factor the quadratic....

OpenStudy (anonymous):

For Part A: (sorry campbell_st) 3x^(2)y^(2)-xy^(2)-2y^(2) Factor out the GCF of y^(2) from the expression 3x^(2)y^(2). y^(2)(3x^(2))-xy^(2)-2y^(2) Factor out the GCF of y^(2) from the expression -xy^(2). y^(2)(3x^(2))+y^(2)(-x)-2y^(2) Factor out the GCF of y^(2) from the expression -2y^(2). y^(2)(3x^(2))+y^(2)(-x)+y^(2)(-2) Factor out the GCF of y^(2) from 3x^(2)y^(2)-xy^(2)-2y^(2). y^(2)(3x^(2)-x-2)

OpenStudy (anonymous):

@Guyzrc00l A: 3x^2y^2-xy^2-2y^2 B: x^2+6x+9 C: x2-25

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

@Guyzrc00l welcome

OpenStudy (campbell_st):

but the problem is that in PART A... @Guyzrc00l hasn't factored the quadratic equation for you...

OpenStudy (anonymous):

For part A: Checked with a powerful calculator also. 3x^2y^2 - xy^2 - 2y^2 y^2(3x^2) - xy^2 - 2y^2 y^2(3x^2) + y^2(-x)+y^2(-2) y^2 (3x^2 - x - 2)

OpenStudy (anonymous):

Same result @campbell_st

OpenStudy (anonymous):

@Guyzrc00l TO make sure the answer is right??

OpenStudy (campbell_st):

but if you read my post... I said that the quadratic can be factored.... without a powerful calculator.... PART A \[y^2(3x^2 - x -2) = y^2 (3x +2)(x -1)\]

OpenStudy (anonymous):

The question just asked to factor it. Simple.

OpenStudy (campbell_st):

yes.... andthe question is about factoring quadratics.... which means you would need to fully factor each expression....

OpenStudy (anonymous):

Well, ok fine. You are right too. The result will be then.... (3x + 2) (x - 1) y^2

OpenStudy (anonymous):

For Part B: x^2 + 6x + 9 (x + 3)(x + 3) (x + 3)^(1+1) (x + 3)^2

OpenStudy (anonymous):

I'm assuming that x2-25 is actually "x^2-25" For Part C: x^2 - 25 The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b). (x - 5)(x + 5)

OpenStudy (anonymous):

@Guyzrc00l for (3x+2) (x-1) y^2 that is for part a??

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

That is the last step

OpenStudy (anonymous):

@Guyzrc00l Nope, Part C dose not have a exponent

OpenStudy (anonymous):

@campbell_st A little help here? If you don't mind.

OpenStudy (anonymous):

@Guyzrc00l Nope, it does not I looked it's a regular two that's where i am thrown for a loop

OpenStudy (anonymous):

oh, make you could take a snippet of it. Is it on a computer?

OpenStudy (campbell_st):

the last looks like (x -5)(x+5) the difference of 2 squares...

OpenStudy (anonymous):

@Guyzrc00l Yes, i am on a computer I don't know how to take a picture of it and put it on here??

OpenStudy (anonymous):

@pbrianna100 said that there isn't an exponent after x. And that it isn't a normal 2

OpenStudy (anonymous):

Are you using windows or mac?

OpenStudy (anonymous):

@Guyzrc00l I have a windows 7 on my computer

OpenStudy (anonymous):

click Start and type Snipping Tool

OpenStudy (anonymous):

@Guyzrc00l Okay, I did what to do next?

OpenStudy (anonymous):

Select the area with the problem and save it on your computer

OpenStudy (anonymous):

You'll have to open the program first of course. "Snipping Tool"

OpenStudy (anonymous):

@Guyzrc00l I did that, I just don't know how to upload it to here now

OpenStudy (anonymous):

Oh, there is a attach File on the bottom of the text box where you type. :)

OpenStudy (anonymous):

OpenStudy (anonymous):

@Guyzrc00l Okay I uploaded it i think you can see it now lol

OpenStudy (campbell_st):

@Guyzrc00l has aleady posted the correct solution... I'd say a typo.. bu the teacher

OpenStudy (anonymous):

I really do think it is a mistake. I use FLVS curriculum too and I noticed a few mistakes also.

OpenStudy (anonymous):

@Guyzrc00l So you really think it is a exponent for part C??

OpenStudy (anonymous):

What do you think for part D @campbell_st ?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

That's how it usually works.

OpenStudy (campbell_st):

they all have a term in x^2.... and they could all be factored

OpenStudy (anonymous):

Ok, Campbell_st answered for part D.

OpenStudy (anonymous):

@Guyzrc00l Do we know what part D is??

OpenStudy (anonymous):

@Guyzrc00l Yes, I think they have a common what about you??

OpenStudy (anonymous):

Yes, I believe that all of them have a common factor which is x^2.

OpenStudy (anonymous):

@Guyzrc00l Okay good I thought it was me. :) do you mind still helping me still :)??

OpenStudy (anonymous):

Well, I don't mind but I have to go do my own work now. I'm really sorry. Hope some around from here could help you.

OpenStudy (anonymous):

Really sorry.

OpenStudy (anonymous):

@Guyzrc00l Okay. Thanks anyway you really did help me

OpenStudy (anonymous):

You're welcome. Bye

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