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Mathematics 8 Online
OpenStudy (anonymous):

Equation in replies...Will give medal Which represents the sum of series: 144 153 270 90

OpenStudy (anonymous):

Where is the equation?

OpenStudy (anonymous):

OpenStudy (anonymous):

From j = 1 to 4, find the sum of (3j)^2. That is equal to: 3(1)^2 + 3(2)^2 + 3(3)^2 + 3(4)^2 Am I missing something after the exponent, because it looks cut off

OpenStudy (anonymous):

No its just a questionmark after the exponent

OpenStudy (anonymous):

I believe you can do the rest, right?

OpenStudy (anonymous):

I sure hope so but if i need any more help i will let you know

OpenStudy (anonymous):

What answer did you get

OpenStudy (anonymous):

By the way, I did 3(3)^2 in laziness, it should be (3*3)^2, not 3*(3^2)

OpenStudy (anonymous):

I don't agree. This is (3 * 1)^2 + (3 * 2)^2 + (3 * 3)^2 + (3 * 3)^2

OpenStudy (anonymous):

But it ends at j=4, so the final term would be ..+(3*4)^2

OpenStudy (anonymous):

I got 270. Idk if thats correct but thats what i got

OpenStudy (anonymous):

Yes, that is the answer

OpenStudy (anonymous):

You're right about last term, @larryboxaplenty . I slipped.

OpenStudy (anonymous):

270 is the result I got writing a short program.

OpenStudy (anonymous):

There is also a shortcut, but it's more useful if the number of terms is above 10

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