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Mathematics 7 Online
OpenStudy (anonymous):

Which represents the series in sigma notation: 1 + 1/2 + 1/4 + 1/16 + 1/32 + 1/64 Choices in replies

OpenStudy (anonymous):

OpenStudy (anonymous):

@larryboxaplenty

OpenStudy (anonymous):

Hello! So, if we rewrite the summation terms a bit, I bet you'll be able to see the pattern yourself. Take a look at it if I write it this way: \[\frac{1}{1} + \frac{1}{2} + \frac{1}{4} + \frac{1}{16} + \frac{1}{32} + \frac{1}{64}\] Do you see a pattern?

OpenStudy (anonymous):

I think there is a term missing, as well.

OpenStudy (anonymous):

multiplying by 2

OpenStudy (anonymous):

Ok! So each term, we multiply by 2 in the denominator. This is the same as multiplying the entire thing by 1/2. Now, the first term is 1. Do we know of a way to make it so that: \[(\frac{1}{2})^a = 1\]

OpenStudy (anonymous):

multiply it by 2

OpenStudy (anonymous):

Or raise it to the zero power.

OpenStudy (anonymous):

So, let's go with raising it to the zero power. That makes the first entry "1." The next entry is 1/2, which is just 1/2 raised to the first power. Then 1/4, which is 1/2 squared. Then 1/8, which is 1/2 cubed. Right?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Ok, so when i = 1, we were raising 1/2 to the 0 power. When i = 2, we raised 1/2 to the power of 1. i = 3, power of 2 i = 4, power of 3. What is the relationship between the power and the value of i?

OpenStudy (anonymous):

exponent = i-1 right?

OpenStudy (anonymous):

Yes

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