Can someone check my answers?
Consider the following reaction occurring in a closed chemical system. Assume that this reaction is at equilibrium and that in general the reaction to the right is favored. CH3CH2OH + 3O2 2CO2 + 3H2O ∆H = –1,235 kJ/mol • What type of chemical reaction is this? • If more CH3CH2OH is added to the system, how will the reactions shift to reach equilibrium again? • If water is extracted from the system, how will the reactions shift to reach equilibrium again? • If heat is removed from the system, how will the reactions shift to reach equilibrium again? • What is the name of the principle that helps you predict each of these shifts in equilibrium?
For the first one the reaction is spontaneous
For the third one it will get rid of all the water and find a substitute.
@Frostbite can you help me
Heard about Le Chatelier's principle?
a little but i didnt really get it
Right this what the questions is all about.
But first we need two other words: Exothermic and endothermic. Heard about these before?
yes
Good. So is the reaction CH3CH2OH + 3O2 -> 2CO2 + 3H2O exothermic or endothermic? (the first question)
endothermic?
Not quite. Remember the rule: Exothermic: \(\Delta H<0\) Endothermic: \(\Delta H>0\) Try again :)
OH yea so since its greater then 0 its exothermic
Exactly.
Now I fast jump to #5 "What is the name of the principle that helps you predict each of these shifts in equilibrium?" I gave you the answer (me being stupid)... so what is the answer?
Le Chatelier's principle
Exactly. Now I like you to try explain #2 and #3 using the principle, if you can handle #4 too, you can try it, otherwise we save it for a little while.
Could you review the principle a little
The principle in a nutshell say: Interference with an equilibrium system promotes changes that diminish the effect of the intervention. What does this mean and what is the consequence? If a system is changed in a way that increases the concentration of one of the reacting species, it will favor the reaction in which the increased specie(s) is consumed. This principle also applies to pressure and heat. \[\Large Q=\frac{ [\textrm{CO}_{2}]^2 \times [\textrm{H}_2\textrm{O}]^3 }{ [\textrm{CH}_{3}\textrm{CH}_{2}\textrm{OH}] \times [\textrm{O}_{2}]^3 }\]
For the second one wont it shift up
Are you sure? If you add more ethanol (CH3CH2OH). Look at what I wrote: "If a system is changed in a way that increases the concentration of one of the reacting species, it will favor the reaction in which the increased specie(s) is consumed." We add ethanol, so what happens with it?
What way do we push the reaction?|dw:1397865165239:dw|
down
You mean towards H2O and CO2?
yes
Exactly! :) What about #3 then? Now we REMOVE water.
it would to towards the other side right
You mean towards H2O and CO2 (just asking to be sure)?
No towards the CH3CH2OH + O2
Ahhhh, this time we don't add water, but we remove it, meaning that we like more water created to create equilibrium. So it would be the other way around. You see that?
Oh okay
:) nearly in house. The last one is a bit tricky, but I will allow you to guess there are 50/50 chance and I help by saying it relates to the reaction being exothermic.
the heat would find a release point
I try help you a bit. In an exothermic reaction, the system gives energy as heat to the surroundings. If we now add heat to the system by rising the temperature, the equilibrium is shifted towards the reactants. Can you guess the answer now?
the head would spread out in the equation
It would push it towards the products (H2O and CO2). I can see Le Chatelier's principle indeed are causing some problems. May I suggest you read the following link: http://chemwiki.ucdavis.edu/Physical_Chemistry/Equilibria/Le_Chatelier's_Principle Perhaps it can help you to a better understanding. Still I like to help you, all you gotta do is to message me.
Okay Ill chekc it out thanks
No problems at all. Best of luck with everything, if you are having problems, don't hesitate writing to me.
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