Question

ELECTROLYSIS: How do you find the product of Copper sulphate(CuSO4) at the anode and cathode .And the half equations at the anode and cathode

Answer 1

At Anode:
4OH- (aq) → 2H2O (l) + O2 (g) + 4e-
At Cathode:
Cathode: Cu2+ (aq) + 2e- → Cu (s)

Overall reaction:
2CuSO4 (aq) + 2H2O (l) → 2Cu (s) + 2H2SO4 (aq) + O2 (g)