Question

After the fraction x+1/3 - x+2/2x have been combined using the Least Common Denominator of 6x, what is the numerator?

Answer 1

could this be
\[\large \frac{x+1}{3}-\frac{x+2}{2x}\]?

Answer 2

Do I first multiply the first fraction by 2x/2x and the second fraction by 3/3? and yes that is the expression :)

Answer 3

yes that is what you do exactly

Answer 4

I get 2x^2+1/6x - 3x+2/6x?

Answer 5

hmm no i don't think so

Answer 6

Should I simplify to 2x^2+3x+3/6x

Answer 7

first of all you have too many fraction bars there, i assume you meant
\[\frac{2x^2+1}{6x}-\frac{3x+2}{6x}\] but that is also wrong, you have to distribute when you multiply

Answer 8

Would you show me? Please :)

Answer 9

\[\large \frac{x+1}{3}-\frac{x+2}{2x}\]
\[\frac{2x}{2x}\times \frac{x+1}{3}-\frac{3}{3}\frac{x+2}{2x}\] is right but you have to think of it as
\[\frac{2x}{2x}\times \frac{(x+1)}{3}-\frac{3}{3}\times \frac{(x+2)}{2x}\]

Answer 10

Ah, so I should get 2x^2 + 2x for the first fractions numerator, 6x for the first fractions denominator?

Answer 11

the numerator and and denominator of a fraction carry their own parentheses even if you don't see them
think "order of operations"
when you multiply you will get
\[\frac{2x^2+2x-3x-6}{6x}\]

Answer 12

Then simplify right? To 2x^2 -1x - 6 over 6x

Answer 13

yes

Answer 14

or keep it, no simplification

Answer 15

okay thanks!! :):)

Answer 16

i would call that "combine like terms" there is no such mathematical operation as "simplify" no matter how many times your math teacher says it
it is not real

Answer 17

yw

Answer 18

Haha, I understand and thank you really, much appreciated! Very helpful c:::

Answer 19

thanks